<p><p>3x + 2y = 3 } 3x + 2y = 3</p>
<p>2(x – y) = 12 } 2x – 2y = 12</p>
<p> 5x + 0y = 15</p>
<p>5x = 15</p>
<p>X = 15/5 = 3</p>
<p>3(3) + 2y = 3</p>
<p>9 + 2y = 3</p>
<p>9 - 3 = 2y</p>
<p>6 = 2y</p>
<p>y = 6/2 = 3</p>
<p> </p>
</p>
<p>gaizki dago</p>
<p>x=3 y=-3</p>
<p>ondo aingeru!</p>
Iruzkinak
Erika 2013-04-24 20:24 #1
<p>
<p>3x + 2y = 3 } 3x + 2y = 3</p>
<p>2(x – y) = 12 } 2x – 2y = 12</p>
<p> 5x + 0y = 15</p>
<p>5x = 15</p>
<p>X = 15/5 = 3</p>
<p>3(3) + 2y = 3</p>
<p>9 + 2y = 3</p>
<p>9 - 3 = 2y</p>
<p>6 = 2y</p>
<p>y = 6/2 = 3</p>
<p> </p>
</p>
Ramon 2013-04-29 21:36 #2
<p>gaizki dago</p>
Aingeru Astigarraga 2013-05-02 18:49 #3
<p>x=3 y=-3</p>
Ramon 2013-05-03 16:16 #4
<p>ondo aingeru!</p>
Utzi iruzkina: